Gujarati
Mathematical Reasoning
medium

$(p\; \wedge \sim q) \wedge (\sim p \wedge q)$ is

A

A tautology

B

A contradiction

C

Both a tautology and a contradiction

D

Neither a tautology nor a contradiction

Solution

(b) $(p\; \wedge \sim q) \wedge (\sim p \wedge q) = (p\; \wedge \sim p) \wedge (\sim q \wedge q) = f \wedge f = f$.

(By using associative laws and commutatine laws)

 $(p\ \wedge \sim q) \wedge (\sim p \wedge q)$ is a contradiction.

Standard 11
Mathematics

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