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Mathematical Reasoning
medium
$(p\; \wedge \sim q) \wedge (\sim p \wedge q)$ is
A
A tautology
B
A contradiction
C
Both a tautology and a contradiction
D
Neither a tautology nor a contradiction
Solution
(b) $(p\; \wedge \sim q) \wedge (\sim p \wedge q) = (p\; \wedge \sim p) \wedge (\sim q \wedge q) = f \wedge f = f$.
(By using associative laws and commutatine laws)
$(p\ \wedge \sim q) \wedge (\sim p \wedge q)$ is a contradiction.
Standard 11
Mathematics