If Delta Q and Delta W represent heat supplied to system and work done on system respectively, then

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11.Thermodynamics

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If $\Delta Q$ and $\Delta W$ represent the heat supplied to the system and the work done on the system respectively, then the first law of thermodynamics can be written as

where $\Delta U$ is the internal energy

$\Delta Q = \Delta U + \Delta W$

$\Delta Q = \Delta U - \Delta W$

$\Delta Q = \Delta W - \Delta U$

$\Delta Q = - \Delta W - \Delta U$

Solution

(b)From FLOT $\Delta Q = \Delta U + \Delta W$
Heat supplied to the system so $\Delta Q →$ Positive
and work is done on the system so $\Delta W →$ Negative
Hence +$\Delta Q = \Delta U – \Delta W$

Standard 11

Physics

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$P-V$ plots for two gases during adiabatic process are shown. Plots $(1)$ and $(2)$ corresponds to

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If $\Delta Q$ and $\Delta W$ represent the heat supplied to the system and the work done on the system respectively, then the first law of thermodynamics can be written as where $\Delta U$ is the internal energy

Solution

Similar Questions

During an adiabatic process, the volume of gas is found to be inversely proportional to the cube of its temperature. The ratio of $\frac{{{C_p}}}{{{C_v}}}$ for the gas is

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If $\Delta Q$ and $\Delta W$ represent the heat supplied to the system and the work done on the system respectively, then the first law of thermodynamics can be written as

where $\Delta U$ is the internal energy