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2. Electric Potential and Capacitance
easy
If $3$ charges are placed at the vertices of equilateral triangle of charge ‘$q$’ each. What is the net potential energy, if the side of equilateral triangle is $l\, cm$
A
$\frac{1}{{4\pi {\varepsilon _0}}}\frac{{{q^2}}}{l}$
B
$\frac{1}{{4\pi {\varepsilon _0}}}\frac{{2{q^2}}}{l}$
C
$\frac{1}{{4\pi {\varepsilon _0}}}\frac{{3{q^2}}}{l}$
D
$\frac{1}{{4\pi {\varepsilon _0}}}\frac{{4{q^2}}}{l}$
Solution
(c) $U = \frac{1}{{4\pi {\varepsilon _0}}}.\frac{{{Q_1}{Q_2}}}{r};$ net potential energy
${U_{net}} = 3 \times \frac{1}{{4\pi {\varepsilon _0}}}.\frac{{{q^2}}}{l}$
Standard 12
Physics