If ${a_n} = \sum\limits_{r = 0}^n {} \frac{1}{{^n{C_r}}}$ then $\sum\limits_{r = 0}^n {} \frac{r}{{^n{C_r}}}$ equals

  • [IIT 1998]
  • A

    $(n - 1)\;{a_n}$

  • B

    $n{a_n}$

  • C

    $\frac{1}{2}n{a_n}$

  • D

    None of these

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