If ${a_n} = \sum\limits_{r = 0}^n {} \frac{1}{{^n{C_r}}}$ then $\sum\limits_{r = 0}^n {} \frac{r}{{^n{C_r}}}$ equals
$(n - 1)\;{a_n}$
$n{a_n}$
$\frac{1}{2}n{a_n}$
None of these
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