The number of ways of dividing $52$ cards amongst four players so that three players have $17$ cards each and the fourth player just one card, is
$\frac{{52\;!}}{{{{(17\;!)}^3}}}$
$52\;!$
$\frac{{52\;!}}{{17\;!}}$
None of these
Let $n(A) = 3, \,n(B) = 3$ (where $n(S)$ denotes number of elements in set $S$), then number of subsets of $(A \times B)$ having odd number of elements, is-
The English alphabet has $5$ vowels and $21$ consonants. How many words with two different vowels and $2$ different consonants can be formed from the alphabet?
Number of different words that can be formed from all letters of word $APPLICATION$ such that two vowels never come together is -
$^n{C_r}{ + ^{n - 1}}{C_r} + ......{ + ^r}{C_r}$ =
Six ‘$+$’ and four ‘$-$’ signs are to placed in a straight line so that no two ‘$-$’ signs come together, then the total number of ways are