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3 and 4 .Determinants and Matrices
normal
If $A =$ $\left[ {\begin{array}{*{20}{c}}3&4\\1&{ - 6}\end{array}} \right]$ and $B =$ $\left[ {\begin{array}{*{20}{c}}{ - 2}&5\\6&1\end{array}} \right]$ then $X$ such that $A + 2X = B$ equals
A$\left[ {\begin{array}{*{20}{c}}2&3\\{ - 1}&0\end{array}} \right]$
B$\left[ {\begin{array}{*{20}{c}}3&5\\{ - 1}&0\end{array}} \right]$
C$\left[ {\begin{array}{*{20}{c}}5&2\\{ - 1}&0\end{array}} \right]$
Dnone of these
Solution
$X =$ $\frac{1}{2}$ $(B – A)$ $=$ $\frac{1}{2}$ $\left[ {\begin{array}{*{20}{c}}{ – 5}&1\\5&7\end{array}} \right]$
Standard 12
Mathematics