If $Q$ is the charge on the plates of a capacitor of capacitance $C, V$ the potential difference between the plates, $A$ the area of each plate and $d $ the distance between the plates, the force of attraction between the plates is
If $Q$ is the charge on the plates of a capacitor of capacitance $C, V$ the potential difference between the plates, $A$ the area of each plate and $d $ the distance between the plates, the force of attraction between the plates is
- A
$\frac{1}{2}\,\,\left( {\frac{{{Q^2}}}{{{\varepsilon _0}\,A}}} \right)$
- B
$\frac{1}{2}\,\,\left( {\frac{{C{V^2}}}{d}} \right)$
- C
$\frac{1}{2}\,\,\left( {\frac{{C{V^2}}}{{A\,{\varepsilon _0}}}} \right)$
- D
$A$ and $B$ both
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