If a body looses half of its velocity on pene | vedclass

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Question

(a)For first condition Initial velocity $= u$, Final velocity $= u/2, s = 3 \,cm $ From ${v^2} = {u^2} - 2as$

==> ${\left( {\frac{u}{2}} \right)

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(a)For first condition Initial velocity $= u$, Final velocity $= u/2, s = 3 \,cm $ From ${v^2} = {u^2} - 2as$

==> ${\left( {\frac{u}{2}} ight)^2} = {u^2} - 2as$

==> $a = \frac{{3{u^2}}}{{8s}}$

Second condition Initial velocity$ = u/2$, Final velocity $= 0$ From ${v^2} = {u^2} - 2ax$

==>$0 = \frac{{{u^2}}}{4} - 2ax$  

$x = \frac{{{u^2}}}{{4 	imes 2a}} = \frac{{{u^2} 	imes 8s}}{{4 	imes 2 	imes 3{u^2}}} = s/3 = 1\,cm$

If a body looses half of its velocity on penetrating $3 \,cm$ in a wooden block, then how much will it penetrate more before coming to rest ........... $cm$

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