13.Oscillations
easy

If a body of mass $0.98\, kg$ is made to oscillate on a spring of force constant $4.84\, N/m$, the angular frequency of the body is ..... $ rad/s$

A

$1.22$

B

$2.22$

C

$3.22 $

D

$4.22$

Solution

$\omega = \sqrt {k/m} = \sqrt {\frac{{4.84}}{{0.98}}} = 2.22\;rad/\sec $

Standard 11
Physics

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