If a body starts from rest and travels 120,, cm in 6^{th} second then acceleration of body is

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2.Motion in Straight Line

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If a body starts from rest and travels $120\,\, cm$ in $6^{th}$ second then the acceleration of body is

A$\frac{240}{11}\,\, m/s^2$

B$\frac{120}{11}\,\, m/s^2$

C$11\,\, cm/s^2$

D$21.8\,\, cm/s^2$

Solution

Using $S_{n}=u+\frac{1}{2} a(2 n-1),$ we get $S_{6}=u+\frac{a}{2}(2 \times 6-1)$ i.e.
$1.2=0+\frac{a}{2}(11) i . e . a=21.8 \mathrm{m} s^{-2}$

Standard 11

Physics

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