A scooter accelerates from rest for time t_{1} at constant rate a

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2.Motion in Straight Line

hard

A scooter accelerates from rest for time $t_{1}$ at constant rate $a _{1}$ and then retards at constant rate $a _{2}$ for time $t _{2}$ and comes to rest. The correct value of $\frac{t_{1}}{t_{2}}$ will be ..... .

A$\frac{a_{1}+a_{2}}{a_{2}}$

B$\frac{ a _{2}}{ a _{1}}$

C$\frac{ a _{1}}{ a _{2}}$

D$\frac{a_{1}+a_{2}}{a_{1}}$

(JEE MAIN-2021)

Solution

Draw vt curve
$\tan \theta_{1}=a_{1}=\frac{v_{\max }}{t_{1}}$ And $\tan \theta_{2}=a_{2}=\frac{v_{\max }}{t_{2}}$
$\div$ above
$\frac{t_{1}}{t_{2}}=\frac{a_{2}}{a_{1}}$

Standard 11

Physics

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hard

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easy

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easy

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medium

(JEE MAIN-2023)

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