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2.Motion in Straight Line
hard
A scooter accelerates from rest for time $t_{1}$ at constant rate $a _{1}$ and then retards at constant rate $a _{2}$ for time $t _{2}$ and comes to rest. The correct value of $\frac{t_{1}}{t_{2}}$ will be ..... .
A$\frac{a_{1}+a_{2}}{a_{2}}$
B$\frac{ a _{2}}{ a _{1}}$
C$\frac{ a _{1}}{ a _{2}}$
D$\frac{a_{1}+a_{2}}{a_{1}}$
(JEE MAIN-2021)
Solution
Draw vt curve$\tan \theta_{1}=a_{1}=\frac{v_{\max }}{t_{1}}$ And $\tan \theta_{2}=a_{2}=\frac{v_{\max }}{t_{2}}$
$\div$ above
$\frac{t_{1}}{t_{2}}=\frac{a_{2}}{a_{1}}$
Standard 11
Physics
