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4-1.Newton's Laws of Motion
medium
If a bullet of mass $5 \,gm$ moving with velocity $100 \,m /sec$, penetrates the wooden block upto $6 \,cm$. Then the average force imposed by the bullet on the block is ........... $N$
A
$8300$
B
$417$
C
$830$
D
$0$
Solution
(b) $u = 100\;m/s,\;v = 0,\;s = 0.06\;m$
Retardation $ = a = \frac{{{u^2}}}{{2s}} = \frac{{{{(100)}^2}}}{{2 \times 0.06}} = \frac{{1 \times {{10}^6}}}{{12}}$
$\therefore $ Force $ = ma = \frac{{5 \times {{10}^{ – 3}} \times 1 \times {{10}^6}}}{{12}} = \frac{{5000}}{{12}} = 417\;N$
Standard 11
Physics
