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4.Moving Charges and Magnetism
easy
If a charged particle goes unaccelerated in a region containing electric and magnetic fields
A
$\vec E$ must be parallel to $\vec B$
B
$\vec v$ must be perpendicular to $\vec E$
C
$\vec v$ must be perpendicular to $\vec B$
D
$E$ must be equal to $vB$
Solution
If a charged particle goes unaccelerated in a region containing electric and magnetic fields, force due to electric and magnetic field is equal
$|q \vec{E}|=q|\vec{v} \times \vec{B}|$
$\Rightarrow|\vec{E}|=|\vec{v} \times \vec{B}|$
$\vec{E} \perp \vec{B}$ and $\vec{E} \perp \vec{v}$
$\Rightarrow E=v B \sin \theta,$ not necessarily to $v B$ since sin $\theta$ is not necessarily equal to one.
Standard 12
Physics
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