Gujarati
Hindi
4.Moving Charges and Magnetism
easy

If a charged particle goes unaccelerated in a region containing electric and magnetic fields

A

$\vec E$ must be parallel to $\vec B$

B

$\vec v$ must be perpendicular to $\vec E$

C

$\vec v$ must be perpendicular to $\vec B$

D

$E$ must be equal to $vB$

Solution

If a charged particle goes unaccelerated in a region containing electric and magnetic fields, force due to electric and magnetic field is equal

$|q \vec{E}|=q|\vec{v} \times \vec{B}|$

$\Rightarrow|\vec{E}|=|\vec{v} \times \vec{B}|$

$\vec{E} \perp \vec{B}$ and $\vec{E} \perp \vec{v}$

$\Rightarrow E=v B \sin \theta,$ not necessarily to $v B$ since sin $\theta$ is not necessarily equal to one.

Standard 12
Physics

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