Two charged particles of mass $m$ and charge $q$ each are projected from origin simultaneously with same speed $V$ in transverse magnetic field. If ${\vec r_1}$ and ${\vec r_2}$ are the position vectors of particles (with respect to origin) at $t = \frac{{\pi m}}{{qB}}$ then the value of ${\vec r_1}.{\vec r_2}$ at that time is
${\left( {\frac{{mv}}{{qB}}} \right)^2}$
$\frac{1}{2}{\left( {\frac{{mv}}{{qB}}} \right)^2}$
$2{\left( {\frac{{mv}}{{qB}}} \right)^2}$
$4{\left( {\frac{{mv}}{{qB}}} \right)^2}$
A proton and an electron both moving with the same velocity $v$ enter into a region of magnetic field directed perpendicular to the velocity of the particles. They will now move in circular orbits such that
Show that a force that does no work must be a velocity dependent force.
A charged particle enters a uniform magnetic field with velocity vector making an angle of $30^o$ with the magnetic field. The particle describes a helical trajectory of pitch $x$ . The radius of the helix is
The dimension of the magnetic field intensity $B$ is
The radius of curvature of the path of a charged particle moving in a static uniform magnetic field is