If a cycle wheel of radius 4 ,m completes one revolution in two seconds. Then acceleration of a poin

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3-2.Motion in Plane

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If a cycle wheel of radius $4 \,m$ completes one revolution in two seconds. Then acceleration of a point on the cycle wheel will be

A${\pi ^2}m/{s^2}$

B$2{\pi ^2}m/{s^2}$

C$4{\pi ^2}m/{s^2}$

D$8\pi \,m/{s^2}$

Solution

(c)Centripetal acceleration$ = 4{\pi ^2}{n^2}r = 4{\pi ^2}{\left( {\frac{1}{2}} \right)^2} \times 4 = 4{\pi ^2}$

Standard 11

Physics

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