If a dice is thrown twice, then probability of getting 1 in first throw only is

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14.Probability

easy

If a dice is thrown twice, then the probability of getting $1$ in the first throw only is

A

$\frac{1}{{36}}$

B

$\frac{3}{{36}}$

C

$\frac{5}{{36}}$

D

$\frac{1}{6}$

Solution

(c) Probability of getting $1$ in first throw $ = \frac{1}{6}$

Probability of not getting $1$ in second throws $ = \frac{5}{6}$

Both are independent events,

so the required probability $ = \frac{1}{6} \times \frac{5}{6} = \frac{5}{{36}}$.

Standard 11

Mathematics

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