If a dice is thrown twice, then the probability of getting $1$ in the first throw only is
If a dice is thrown twice, then the probability of getting $1$ in the first throw only is
- A
$\frac{1}{{36}}$
- B
$\frac{3}{{36}}$
- C
$\frac{5}{{36}}$
- D
$\frac{1}{6}$
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