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14.Probability
medium
The chance of India winning toss is $3/4$. If it wins the toss, then its chance of victory is $4/5$ otherwise it is only $1/2$. Then chance of India's victory is
A
$\frac{1}{5}$
B
$\frac{3}{5}$
C
$\frac{3}{{40}}$
D
$\frac{{29}}{{40}}$
Solution
(d) There are two mutually exclusive cases for the event.
$A = $ India wins the toss and wins the match.
$B = $ India losses the toss and wins the match
$\therefore$ Required probability
$ = P(A) + P(B) = \frac{3}{4} \times \frac{4}{5} + \frac{1}{4} \times \frac{1}{2} = \frac{{29}}{{40}}$.
Standard 11
Mathematics
