If a force of 250, N act on body, momentum acquired is 125, kg-m/s . period for which force acts on

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4-1.Newton's Laws of Motion

easy

If a force of $250\, N$ act on body, the momentum acquired is $125\, kg-m/s$. What is the period for which force acts on the body ......... $\sec$

A

$0.5$

B

$0.2 $

C

$0.4$

D

$0.25$

Solution

(a) Change in momentum = Impulse

$⇒$ $\Delta p = F \times \Delta t \Rightarrow \Delta t = \frac{{\Delta p}}{F} = \frac{{125}}{{250}} = 0.5\;\sec $

Standard 11

Physics

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