If a lighter body (mass ${M_1}$ and velocity ${V_1}$) and a heavier body (mass ${M_2}$ and velocity ${V_2}$) have the same kinetic energy, then
${M_2}{V_2} < {M_1}{V_1}$
${M_2}{V_2} = {M_1}{V_1}$
${M_2}{V_1} = {M_1}{V_2}$
${M_2}{V_2} > {M_1}{V_1}$
A body of mass $5\; kg$ is moving with a momentum of $10\; kg m / s$. A force of $0.2\; N$ acts on it in the direction of motion of the body for $10\; sec$. Find the increase in its kinetic energy.
A $50\,kg$ man with $20\,kg$ load on his head climbs up $20$ steps of $0.25\,m$ height each. The work done in climbing is......$J$
Four particles $A, B, C, D$ of mass $\frac{\mathrm{m}}{2}, \mathrm{~m}, 2 \mathrm{~m}, 4 \mathrm{~m}$, have same momentum, respectively. The particle with maximum kinetic energy is:
A body of mass $5\,kg$ is moving with a momentum of $10\,kg\,ms ^{-1}$. Now a force of $2\,N$ acts on the body in the direction of its motion for $5\,s$. The increase in the Kinetic energy of the body is $...........J$.
Write the definition of work and kinetic energy.