If a proton enters perpendicularly a magnetic field with velocity v , then time period of revolution

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4.Moving Charges and Magnetism

easy

If a proton enters perpendicularly a magnetic field with velocity $v$, then time period of revolution is $T$. If proton enters with velocity $2 v$, then time period will be

A

$T$

B

$2 T$

C

$3 T$

D

$4 T$

Solution

(a)

$T=\frac{2 \pi m}{q B} \Rightarrow$ independent of $V$.

Standard 12

Physics

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