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13.Nuclei
easy
If a radioactive element having half-life of $30\,min$ is undergoing beta decay, the fraction of radioactive element remains undecayed after $90\,min$. will be :
A
$\frac{1}{8}$
B
$\frac{1}{16}$
C
$\frac{1}{4}$
D
$\frac{1}{2}$
(JEE MAIN-2023)
Solution
$\frac{ N }{ N _0}=\left(\frac{1}{2}\right)^{ t / t \frac{1}{2}}=\left(\frac{1}{2}\right)^{\frac{90}{30}}$
$\frac{ N }{ N _0}=\left(\frac{1}{2}\right)^3=\frac{1}{8}$
Standard 12
Physics
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