If a reaction has the experimental rate expression rate $= K [A]^2[B]$, if the concentration of $A$ is doubled and the concentration of $B$ is halved, the what happens to the reaction rate

Write differential rate expression of following reaction and give its order of reaction :

$2 HI \rightarrow H _{2}+ I _{2}$

$2 NO _{( g )}+ O _{2( g )} \rightarrow 2 NO _{2( g )}$

For reaction $2A + B \to $ products, the active mass of $ B $ is kept constant and that of $A$ is doubled. The rate of reaction will then

The rate of reaction $A + 2B \to 3C$ becomes $72\, times$ when concentration of $A$ is tripled and concentration of $B$ is doubled then the order of reaction with respect to $A$ and $B$ respectively is

Consider following two reaction,

$A \to {\text{Product ;}}\,\, - \frac{{d[A]}}{{dt}} = {k_1}{[A]^o}$

$B \to {\text{Product ;}}\,\, - \frac{{d[B]}}{{dt}} = {k_2}{[B]}$

Units of $k_1$ and $k_2$ are expressed in terms of molarity $(M)$ and time $(sec^{-1})$ as

Which of the following rate laws has an overall order of $0.5$  for reaction involving substances $x$, $y$ and $z$