If a sum of money compounded annually becomes | vedclass

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(d) $A=P\left(1+\frac{R}{100}\right)^{T} \Leftrightarrow 1.44 P=P\left(1+\frac{R}{100}\right)^{2}$

$\Rightarrow \quad(1.2)^{2}=\left(1+\frac{R}{100

Vedclass · Accepted Answer

$20$

Vedclass · Answer

(d) $A=P\left(1+\frac{R}{100}ight)^{T} \Leftrightarrow 1.44 P=P\left(1+\frac{R}{100}ight)^{2}$

$\Rightarrow \quad(1.2)^{2}=\left(1+\frac{R}{100}ight)^{2}$

$\Rightarrow 1+\frac{R}{100}=1.2 \Leftrightarrow R=0.2 	imes 100=20 \%$

If a sum of money compounded annually becomes $1.44$ times of itself in $2$ years, then the rate of interest per annum (In $\%$) is

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