If an electron moves from rest from a point at which potential is 50, volt to another point at which

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2. Electric Potential and Capacitance

easy

If an electron moves from rest from a point at which potential is $50\, volt$ to another point at which potential is $70\, volt$, then its kinetic energy in the final state will be

A

$3.2 × 10^{-10} J$

B

$3.2 × 10^{-18} J$

C

$1\, N$

D

$1 \,dyne$

Solution

(b) $\,{\rm{K}}{\rm{.E}}{\rm{.}}\, = {q_0}({V_A} – {V_B}) = 1.6 \times {10^{ – 19}}(70 – 50) = 3.2 \times {10^{ – 18}}J$

Standard 12

Physics

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