4. STRUCTURE OF THE ATOM
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अगर ब्रोमीन परमाणु दो समस्थानिकों $_{35}^{79}Br$ $(49.7 \%)$ तथा $_{35}^{81}Br$ $(50.3 \%),$ के रूप में है, तो ब्रोमीन परमाणु के औसत परमाणु द्रव्यमान की गणना कीजिए।

A

$0.80\,u $

B

$80.006\,u $

C

$89.006\,u $

D

$88.006\,u $

Solution

It is given that two isotopes of bromine are $_{35}^{79}Br$ $(49.7 \%)$ and $_{35}^{81}Br$ $ (50.3 \%) .$ Then, the average atomic mass of bromine atom is given by :

$79 \times \frac{49.7}{100}+81 \times \frac{50.3}{100}$

$=\frac{3926.3}{100}+\frac{4074.3}{100}$

$=\frac{8000.6}{100}$

$=80.006\,u $

Standard 9
Science

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