7.Gravitation
easy

If earth suddenly stop rotating, then the weight of an object of mass $m$ at equator will $[\omega$ is angular speed of earth and $R$ is its radius]

A

Decrease by $m \omega^2 R$

B

Increase by $m \omega^2 R$

C

Decrease by $m \omega R^2$

D

Increase by $m \omega R^2$

Solution

(b)

At the equator,

Apparent weight, $w^{\prime}=w-m \omega^2 R$

If Earth stops rotating, $w^{\prime}$ will be equal to $\omega$.

Thus, the weight of an object of mass $m$ at equator will increase by $m \omega^2 R$.

Standard 11
Physics

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