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7.Gravitation
easy
If earth suddenly stop rotating, then the weight of an object of mass $m$ at equator will $[\omega$ is angular speed of earth and $R$ is its radius]
A
Decrease by $m \omega^2 R$
B
Increase by $m \omega^2 R$
C
Decrease by $m \omega R^2$
D
Increase by $m \omega R^2$
Solution
(b)
At the equator,
Apparent weight, $w^{\prime}=w-m \omega^2 R$
If Earth stops rotating, $w^{\prime}$ will be equal to $\omega$.
Thus, the weight of an object of mass $m$ at equator will increase by $m \omega^2 R$.
Standard 11
Physics
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