If four persons are chosen at random from a group of $3$ men, $2$ women and $4 $ children. Then the probability that exactly two of them are children, is

  • A

    $\frac{{10}}{{21}}$

  • B

    $\frac{8}{{63}}$

  • C

    $\frac{5}{{21}}$

  • D

    $\frac{9}{{21}}$

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