If maximum energy is stored in capacitor at t =0 then time after which current in circuit will be ma

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7.Alternating Current

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If maximum energy is stored in capacitor at $t =0$ then find the time after which current in the circuit will be maximum.

A

$\frac{\pi}{2} \,ms$

B

$\frac{\pi}{4} \,ms$

C

$\pi \,ms$

D

$2 \,ms$

(AIIMS-2019)

Solution

In $L-C$ oscillation, total time in one complete cycle is calculated as,

$T=2 \pi \sqrt{L C}$

$=2 \pi \sqrt{25 \times 10^{-8} \times 10 \times 10^{-6}}$

$=\pi \times 10^{-3} s$

After time $\frac{T}{4}$ capacitor is fully closed,

The time after which current in the circuit will be maximum,

$\frac{T}{4}=\frac{\pi \times 10^{-3}}{4}=\frac{\pi}{4} ms$

Standard 12

Physics

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