7.Binomial Theorem
normal

If the $6^{th}$ term in the expansion of the binomial ${\left[ {\frac{1}{{{x^{\frac{8}{3}}}}}\,\, + \,\,{x^2}\,{{\log }_{10}}\,x} \right]^8}$ is $5600$, then $x$ equals to

A

$5$

B

$8$

C

$10$

D

$100$

Solution

$T_6 = ^8C_5  {\left( {\frac{1}{{{x^{\frac{8}{3}}}}}} \right)^{8\, – \,5}}. (x^2 log_{10} x)^5 = 100 \Rightarrow x = 10$

Standard 11
Mathematics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.