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7.Gravitation
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If the angular velocity of earth's spin is increased such that the bodies at the equator start floating, the duration of the day would be approximately ........ minutes
(Take : $g =10 \,ms ^{-2},$ the radius of earth, $R =6400 \times 10^{3}\, m ,$ Take $\left.\pi=3.14\right)$
A
$60$
B
$480$
C
$1200$
D
$84$
(JEE MAIN-2021)
Solution
For objects to float
$mg = m \omega^{2} R$
$\omega=$ angular velocity of earth.
$R =$ Radius of earth
$\omega=\sqrt{\frac{g}{R}}$
Duration of day $= T$
$T =\frac{2 \pi}{\omega}$
$\Rightarrow T =2 \pi \sqrt{\frac{ R }{ g }}$
$=2 \pi \sqrt{\frac{6400 \times 10^{3}}{10}}$
$\Rightarrow \frac{ T }{60}=83.775$ minutes
$\simeq 84$ minutes
Standard 11
Physics
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