Gujarati
Hindi
4.Average
easy

If the average of $m$ numbers is $n^{2}$ and that of $n$ numbers is $m^{2}$, then the average of $( m + n )$ numbers is

A

$\frac{m}{n}$

B

$mn$

C

$m-n$

D

$m+n$

Solution

Sum of m numbers $=m n^{2}$, Sum of n number $=n^{2} m^{2}$

Average of $(m+n)=\frac{m n^{2}+n m^{2}}{m+n}=m n$

Standard 13
Quantitative Aptitude

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.