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4.Average
easy
If the average of $m$ numbers is $n^{2}$ and that of $n$ numbers is $m^{2}$, then the average of $( m + n )$ numbers is
A
$\frac{m}{n}$
B
$mn$
C
$m-n$
D
$m+n$
Solution
Sum of m numbers $=m n^{2}$, Sum of n number $=n^{2} m^{2}$
Average of $(m+n)=\frac{m n^{2}+n m^{2}}{m+n}=m n$
Standard 13
Quantitative Aptitude