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1. Electric Charges and Fields
normal
If the charge on a capacitor is increased by $2\, C$ the energy stored in it increases by $21\%$. The original charge on the capacitor (in coulomb) is
A
$10$
B
$20$
C
$30$
D
$40$
Solution
$\frac{\mathrm{Q}^{2}}{2 \mathrm{C}}=\mathrm{\,E}$ and $\frac{(\mathrm{Q}+2)^{2}}{2 \mathrm{C}}=1.21 \mathrm{\,E}$
$\frac{(\mathrm{Q}+2)^{2}}{\mathrm{Q}^{2}}=1.21 \Rightarrow \mathrm{Q}+2=1.1 \mathrm{Q} \Rightarrow \mathrm{Q}=20$
Standard 12
Physics