If the distance between the plates of a capacitor having capacity $C$ and charge $Q$ is doubled then work done will be

  • A

    $\frac{{{Q^2}}}{{4C}}$

  • B

    $\frac{{{Q^2}}}{{2C}}$

  • C

    $\frac{{{Q^2}}}{{C}}$

  • D

    $\frac{{{2Q^2}}}{{C}}$

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