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6-2.Equilibrium-II (Ionic Equilibrium)
medium
If the concentration of $CrO_4^ - $ ions in a saturated solution of silver chromate is $2 \times {10^{ - 4}}.$ Solubility product of silver chromate will be
A
$4 \times {10^{ - 8}}$
B
$8 \times {10^{ - 12}}$
C
$12 \times {10^{ - 12}}$
D
$32 \times {10^{ - 12}}$
Solution
(d) ${K_{sp}}$ of $A{g_2}Cr{O_4} = {[A{g^ + }]^2}\,[Cro_4^{ – \, – }]$
$CrO_4^{ – \, – } = 2 \times {10^{ – 4}}$ then $A{g^ + } = 2 \times 2 \times {10^{ – 4}}$
${K_{sp}} = {(4 \times {10^{ – 4}})^2}\,(2 \times {10^{ – 4}}) = 32 \times {10^{ – 12}}$
Standard 11
Chemistry
