If coordinates of two points are P(-2,3) and Q(-3,5), then (abscissa of P ) - (abscissa of Q ) is

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3. Coordinate Geometry

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If the coordinates of the two points are $P(-2,3)$ and $Q(-3,5),$ then (abscissa of $P$ ) $-$ (abscissa of $Q$) is

A

$-5$

B

$-1$

C

$-2$

D

$1$

Solution

Abscissa of $P (-2,3)=-2$

Abscissa of $Q(-3,5)=-3$

$\therefore($ Abscissa of $P )-($ Abscissa of $Q)=-2-(-3)=-2+3=1$

Standard 9

Mathematics

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