If the interatomic spacing in a steel wire is $3.0Å$ and ${Y_{steel}}$= $20 \times {10^{10}}N/{m^2}$ then force constant is
If the interatomic spacing in a steel wire is $3.0Å$ and ${Y_{steel}}$= $20 \times {10^{10}}N/{m^2}$ then force constant is
- A
$6 \times {10^{ - 2}}\,N/{Å}$
- B
$6 \times {10^{ - 9}}N/{Å}$
- C
$4 \times {10^{ - 5}}\,N/{Å}$
- D
$6 \times {10^{ - 5}}N/{Å}$
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