If length of a pendulum is made 9 times and mass of bob is made 4 times then value of time period be

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13.Oscillations

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If the length of a pendulum is made $9$ times and mass of the bob is made $4$ times then the value of time period becomes

A

$3T$

B

$\frac{3}{2}T$

C

$4T$

D

$2T$

Solution

(a) $T = 2\pi \sqrt {\frac{l}{g}} $

==> $T \propto \sqrt l ,$

hence if l made $9$ times $T$ becomes $3$ times.

Also time period of simple pendulum does not depends on the mass of the bob.

Standard 11

Physics

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