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3-2.Motion in Plane
easy
If the overbridge is concave instead of being convex, the thrust on the road at the lowest position will be
A$mg + \frac{{m{v^2}}}{r}$
B$mg - \frac{{m{v^2}}}{r}$
C$\frac{{{m^2}{v^2}g}}{r}$
D$\frac{{{v^2}g}}{r}$
Solution
(a)Thrust at the lowest point of concave bridge
= $mg + \frac{{m{v^2}}}{r}$
= $mg + \frac{{m{v^2}}}{r}$
Standard 11
Physics
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