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3-2.Motion in Plane
medium
A car is moving with a constant speed of $20\,m / s$ in a circular horizontal track of radius $40\,m$. A bob is suspended from the roof of the car by a massless string. The angle made by the string with the vertical will be : (Take $g =10$ $\left.m / s ^2\right)$
A$\frac{\pi}{6}$
B$\frac{\pi}{2}$
C$\frac{\pi}{4}$
D$\frac{\pi}{3}$
(JEE MAIN-2023)
Solution

$T \sin \theta=\frac{ mv ^2}{ R }$
$\tan \theta=\frac{ v ^2}{ Rg }$
$\tan \theta=\frac{20^2}{40 \times 10}$
$\tan \theta=1$
$\Rightarrow \theta=\frac{\pi}{4}$
Standard 11
Physics