Gujarati
Hindi
2. Electric Potential and Capacitance
medium

If the potential at the centre of a uniformly charged hollow sphere of radius $R$ is $V$ then electric field at a distance $r$ from the centre of the sphere is $(r > R)$

A

$\frac{{VR}}{{{r^2}}}$

B

$\frac{{Vr}}{{{R^2}}}$

C

$\frac{{VR}}{r}$

D

$\frac{{VR}}{{{R^2} + {r^2}}}$

Solution

$\boxed{{\text{V}} = \frac{{{\text{kQ}}}}{{\text{R}}}\,}\, \Rightarrow {\text{E}} = \frac{{{\text{kQ}}}}{{{{\text{r}}^2}}}$

$\frac{V}{E}=\frac{r^{2}}{R} \Rightarrow E=\frac{V R}{r^{2}}$

Standard 12
Physics

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