12.Atoms
normal

If the potential difference applied across $X-$ ray tube is $V$ volts, then approximately minimum wavelength of the emitted $X-$ rays will be

A$\frac{{1227}}{{\sqrt V }}\;\mathring A$
B$\frac{{1240}}{V}\;\mathring A$
C$\frac{{2400}}{V}\;\mathring A$
D$\frac{{12400}}{V}\;\mathring A$

Solution

${\lambda _{\min }} = \frac{{hc}}{{eV}} = \frac{{6.6{ \times ^{ – 34}} \times 3 \times {{10}^8}}}{{1.6 \times {{10}^{ – 19}}V}}$
$ = \frac{{12375}}{V} \approx \frac{{12400}}{V}\;\mathring A$
Standard 12
Physics

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