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14.Probability
easy
If the probabilities of boy and girl to be born are same, then in a $4$ children family the probability of being at least one girl, is
A
$\frac{{14}}{{16}}$
B
$\frac{{15}}{{16}}$
C
$\frac{1}{8}$
D
$\frac{3}{8}$
Solution
(b) Required probability is $1 – P({\rm{no}}\,\,{\rm{girl}})$
$= 1 – {\left( {\frac{1}{2}} \right)^4} = \frac{{15}}{{16}}.$
Standard 11
Mathematics