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14.Probability
normal
Two numbers are selected randomly from the set $S = \{1, 2, 3, 4, 5, 6, 7, 8, 9, 10\}$ without replacement one by one. The probability that minimum of the two numbers is divisible by $3$ or maximum of the two numbers is divisible by $4$ , is
A
$\frac{{23}}{{45}}$
B
$\frac{{37}}{{45}}$
C
$\frac{{16}}{{45}}$
D
$\frac{{19}}{{45}}$
Solution
$P=\frac{2 \times 19}{10 \times 9}=\frac{19}{45}$
favourable : $\{(3,4),(3,5), \ldots \ldots(3,10)$
${(6,7),(6,8), \ldots . .(6,10)} $
${(9,10)}$ ${(1,4),(2,4)} $
${(1,8),(2,8),(4,8),(5,8),(7,8)\}}$
Standard 11
Mathematics
