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14.Probability
easy
If the probability of a horse $A$ winning a race is $1/4$ and the probability of a horse $B$ winning the same race is $1/5$, then the probability that either of them will win the race is
A
$\frac{1}{{20}}$
B
$\frac{9}{{20}}$
C
$\frac{{11}}{{20}}$
D
$\frac{{19}}{{20}}$
Solution
(b) $P(A \cup B) = P(A) + P(B) = \frac{1}{4} + \frac{1}{5} = \frac{9}{{20}}.$
$\{$Since events are mutually exclusive, so $P(A \cap B) = 0\} $
Standard 11
Mathematics