If probability of a horse A winning a race is 1/4 and probability of a horse B winning same race is

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14.Probability

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If the probability of a horse $A$ winning a race is $1/4$ and the probability of a horse $B$ winning the same race is $1/5$, then the probability that either of them will win the race is

A

$\frac{1}{{20}}$

B

$\frac{9}{{20}}$

C

$\frac{{11}}{{20}}$

D

$\frac{{19}}{{20}}$

Solution

(b) $P(A \cup B) = P(A) + P(B) = \frac{1}{4} + \frac{1}{5} = \frac{9}{{20}}.$

$\{$Since events are mutually exclusive, so $P(A \cap B) = 0\} $

Standard 11

Mathematics

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