$A$ and $B$ are events such that $P(A)=0.42$, $P(B)=0.48$ and $P(A$ and $B)=0.16 .$ Determine $P ($ not $A ).$
$A$ and $B$ are events such that $P(A)=0.42$, $P(B)=0.48$ and $P(A$ and $B)=0.16 .$ Determine $P ($ not $A ).$
It is given that $P ( A )=0.42$, $P ( B )=0.48$, $P ( A $ and $B )=0.16$
$P ($ not $A )=1- P ( A )=1-0.42=0.58$
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