A and B are events such that P(A)=0.42 , P(B)=0.48 and P(A and B)=0.16 . Determine P ( not A )

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14.Probability

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$A$ and $B$ are events such that $P(A)=0.42$, $P(B)=0.48$ and $P(A$ and $B)=0.16 .$ Determine $P ($ not $A ).$

A

$0.58$

B

$0.58$

C

$0.58$

D

$0.58$

Solution

It is given that $P ( A )=0.42$, $P ( B )=0.48$, $P ( A $ and $B )=0.16$

$P ($ not $A )=1- P ( A )=1-0.42=0.58$

Standard 11

Mathematics

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