1.Units, Dimensions and Measurement
medium

If the screw on a screw-gauge is given six rotations, it moves by $3\; \mathrm{mm}$ on the main scale. If there are $50$ divisions on the circular scale the least count of the screw gauge is

A

$0.001\; mm$

B

$0.001\; cm$

C

$0.02\; mm$

D

$0.01\; cm$

(JEE MAIN-2020)

Solution

On six rotation, reading of main scale changes by $3 \mathrm{mm} .$

1 rotation corresponds to $\frac{1}{2} \mathrm{mm}$

Also no. of division on circular scale $=50 .$

Least count of the screw gauge will be

$\frac{0.5}{50} \mathrm{mm}=0.001 \mathrm{cm}$

Standard 11
Physics

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