A screw gauge has least count of 0.01, mm and there are 50 divisions in its circular scale. pitch of

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1.Units, Dimensions and Measurement

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A screw gauge has least count of $0.01\, mm$ and there are $50$ divisions in its circular scale. The pitch of the screw gauge is $........mm$

A

$1.0$

B

$0.01$

C

$0.25$

D

$0.5$

(NEET-2020)

Solution

$L.C.$ $=\frac{\text { Pitch }}{\text { Number of division on circular scale }}$

$\Rightarrow 0.01 mm =\frac{\text { Pitch }}{50}$

$\Rightarrow$ Pitch $=0.5 mm$

Standard 11

Physics

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