If system of equations x + 2y + 3z = 4 , x + py + 2z = 3 , x + 4y + μ z = 3 has an infinite number

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3 and 4 .Determinants and Matrices

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If the system of equations $x + 2y + 3z = 4 , x + py + 2z = 3 , x + 4y + \mu z = 3$ has an infinite number of solutions , then :

A

$p = 2 , \mu = 3$

B

$p = 2 , \mu = 4$

C

$3 p = 2 \mu$

D

none of these

Solution

For $2^{nd}$ and $3^{rd}$ equation , $1 = p/4 = 2/\mu = 1$

$==> p = 4 ; \mu = 1$

Standard 12

Mathematics

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