If the terminal speed of a sphere of gold (de | vedclass

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Question

(c)

$V_{	ext {terminal }}=\frac{2 a^2}{9 \eta}(ho-\sigma) g$   $\left\{\begin{array}{l}	ext { Where } \ ho=	ext { density of mate

Vedclass · Accepted Answer

$0.1$

Vedclass · Answer

(c)

$V_{	ext {terminal }}=\frac{2 a^2}{9 \eta}(ho-\sigma) g$   $\left\{\begin{array}{l}	ext { Where } \ ho=	ext { density of material } \ \sigma=	ext { density of liquid }\end{array}ight.$

$\Rightarrow V_T \propto(ho-\sigma)$

$\Rightarrow \frac{V_{T_1}}{V_{T_2}}=\frac{ho_{	ext {gold }}-\sigma_{	ext {liquid }}}{ho_{	ext {silver }}-\sigma_{	ext {liquid }}}$

$\Rightarrow \frac{0.2}{V}=\frac{19.5-1.5}{10.5-1.5}$   $\left\{\begin{array}{l}	ext { Given, } \ V_{T_1}=0.2 \,m / s \ V_{T_2}=V=? \ ho_{	ext {gold }}=19.5 \,kg / m ^3 \ \sigma_{	ext {liquid }}=1.5 \,kg / m ^3 \ ho_{	ext {silver }}=10.5 \,kg / m ^3\end{array}ight.$

$\Rightarrow V=0.1 \,m / s$

If the terminal speed of a sphere of gold (density $19.5 \,kg / m ^2$ ) is $0.2 \,m / s$ in a viscous liquid (density $=1.5 \,kg / m ^3$ ), find the terminal speed of a sphere of silver (density $=10.5 \,kg / m ^3$ ) of the same size in the same liquid is ............ $m / s$

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