If the total energy transferred to a surface in time $t$ is $6.48 \times 10^5 \mathrm{~J}$, then the magnitude of the total momentum delivered to this surface for complete absorption will be :
$2.46 \times 10^{-3} \mathrm{~kg} \mathrm{~m} / \mathrm{s}$
$2.16 \times 10^{-3} \mathrm{~kg} \mathrm{~m} / \mathrm{s}$
$1.58 \times 10^{-3} \mathrm{~kg} \mathrm{~m} / \mathrm{s}$
$4.32 \times 10^{-3} \mathrm{~kg} \mathrm{~m} / \mathrm{s}$
The energy of a photon of light with wavelength $5000\,\mathop A\limits^o $ is approximately $2.5\, eV$. This way the energy of an $X-$ ray photon with wavelength $1\,\mathop A\limits^o $ would be
A beam of light of wavelength $400\,nm$ and power $1.55\,mW$ is directed at the cathode of a photoelectric cell. If only $10 \%$ of the incident photons effectively produce photoelectron, then find current due to these electrons $...........\mu A$
[given, $hc =1240\,eV - nm , e =1.6 \times 10^{-{ }^{19}\,C }$ )
Match the column
$(A)$ Hallwachs $\&$ Lenard | $(P)$ Transformers |
$(B)$ Franck-Hertz | $(Q)$ Microwave |
$(C)$ Klystron valve | $(R)$ Quantization of energy levels |
$(D)$ Nicola Tesla | $(S)$ Photoelectric effect |
Momentum of a photon of wavelength $\lambda$ is
An electron and proton are separated by a large distance. The electron starts approaching the proton with energy $3\, {eV}$. The proton captures the electrons and forms a hydrogen atom in second excited state. The resulting photon is incident on a photosensitive metal of threshold wavelength $4000\, \mathring {{A}}$. What is the maximum kinetic energy of the emitted photoelectron ? (In ${eV}$)